document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=17457>Question 17457</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can you help me solve this problem:    13-8v = 5v+3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #8408 by </B><A HREF=/tutors/aboutme.mpl?userid=tjnw79><B>tjnw79(57)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tjnw79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=8408\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 13-8v = 5v+3<BR>\n" );
document.write( "first subtract 3 on both sides<BR>\n" );
document.write( "-8v+(13)-3=5v+3-(3) to get <BR>\n" );
document.write( "10-8v=5v<BR>\n" );
document.write( "now add 8v to both sides<BR>\n" );
document.write( "10-8v+(8v)=5v+(8v)<BR>\n" );
document.write( "10=13v<BR>\n" );
document.write( "becuse 13 is times v we need to divde 13 on both sides to get you answer<BR>\n" );
document.write( "10/13=v<BR>\n" );
document.write( " </SPAN>\n" );
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