document.write( "Question 1204507: Rachelle has
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Algebra.Com's Answer #840795 by ikleyn(52786) $\"\"$ $\"About$

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\n" ); document.write( "Rachelle has $4.45 in dimes and nickles in her car. The number of nickles is twenty more
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\n" ); document.write( "\n" ); document.write( " Good problem to solve it mentally and to train your mind.\r
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document.write( "Put twenty extra nickels aside, for a minute.\r\n" );
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document.write( "Then the remaining collection consists of equal number of nickels and dimes\r\n" );
document.write( "and is worth 445 - 5*20 = 345 cents.\r\n" );
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document.write( "One nickel PLUS one dime are worth 5+10 = 15 cents;\r\n" );
document.write( "so, there are 345/15 = 23 groups consisting of one nickel and one dime.\r\n" );
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document.write( "From it, we conclude that the initial collection is  23 dimes  and  23 + 20 = 43 nickels.\r\n" );
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document.write( "ANSWER.  23 dimes and 43 nickels.\r\n" );
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document.write( "CHECK.  23*10 + 43*5 = 445 cents = $4.45.    ! correct !\r\n" );
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