document.write( "Question 1204487: Miguel spends $100 on books, five of which are hardcover and the remaining four are paperback. The prices at the bookstore are based on whether the book is hardcover or paperback. It charges $2 less for paperback books than for hardcover books. What is the price for hardcover books? \n" ); document.write( "
Algebra.Com's Answer #840769 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Presumably a formal algebraic solution was wanted, but you can get good mental exercise solving the problem informally, using logical reasoning and simple mental arithmetic. \n" ); document.write( "The five hardbound books each cost $2 more than each paperback. That's 5 times $2 or $10 \"extra\" for the hardbound books. \n" ); document.write( "What is then left is nine books each with the same price, costing a total of $100-$10 = $90. That's $90/9 = $10 per book. \n" ); document.write( "So the paperback books cost $10 each, and the hardbound books each cost $2 more than that. \n" ); document.write( "ANSWER: $12 for each hardbound book. \n" ); document.write( " \n" ); document.write( " |