document.write( "Question 115524: Please help.\r
\n" ); document.write( "\n" ); document.write( "Given f(x)=5x^2-3x+1
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Algebra.Com's Answer #84074 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29=5x%5E2-3x%2B1\" Start with the given function.\r
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\n" ); document.write( "\n" ); document.write( "\"f%28-2%29=5%28-2%29%5E2-3%28-2%29%2B1\" Plug in \"x=-2\". In other words, replace each x with -2.\r
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\n" ); document.write( "\n" ); document.write( "\"f%28-2%29=5%284%29-3%28-2%29%2B1\" Evaluate \"%28-2%29%5E2\" to get 4.\r
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\n" ); document.write( "\n" ); document.write( "\"f%28-2%29=%2B20-3%28-2%29%2B1\" Multiply 5 and 4 to get 20\r
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\n" ); document.write( "\n" ); document.write( "\"f%28-2%29=%2B20%2B6%2B1\" Multiply -3 and -2 to get 6\r
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\n" ); document.write( "\n" ); document.write( "\"f%28-2%29=27\" Now combine like terms
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