document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1204463>Question 1204463</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Pure acid is to be added to a 10​% acid solution to obtain  45L of a 40​% acid solution.<BR>\n" );
document.write( "What amounts of each should be​ used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #840738 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=840738\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is a quick and easy way to solve any 2-part mixture problem like this without using the formal algebraic method shown by the other tutors.<br><BR>\n" );
document.write( "You are starting with 10% acid and adding 100% acid, stopping when you get to 40% acid.  The solution is then in a couple of easy steps.<br><BR>\n" );
document.write( "40% is 1/3 of the way from 10% to 100%.<BR>\n" );
document.write( "Therefore 1/3 of the mixture is the 100% acid that you are adding.<BR>\n" );
document.write( "Since you want 45L of the mixture, the amount of 100% acid you are adding is 1/3 of 45L, or 15L, which means 30L of the 10% acid you started with.<br><BR>\n" );
document.write( "ANSWERS: 30L of the 10% acid, 15L of the 100% acid<br><BR>\n" );
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