document.write( "Question 1204463: Pure acid is to be added to a 10​% acid solution to obtain 45L of a 40​% acid solution.
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document.write( "What amounts of each should be​ used? \n" );
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Algebra.Com's Answer #840736 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answers: \n" ); document.write( "15 liters of pure acid \n" ); document.write( "30 liters of the 10% acid solution\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "============================================================================================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Explanation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are at least two ways to solve this problem. \n" ); document.write( "Method 1 is the standard algebraic approach. \n" ); document.write( "Method 2 is what is taught to pharmacy students.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Method 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Batch A = pure acid = 100% acid \n" ); document.write( "Batch B = 10% acid solution\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = number of liters of batch A \n" ); document.write( "45-x = number of liters of batch B \n" ); document.write( "These two amounts combine to 45 liters total.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = amount of pure acid from batch A \n" ); document.write( "0.10(45-x) = 4.5 - 0.10x = amount of pure acid from batch B \n" ); document.write( "x+(4.5 - 0.10x) = 0.90x+4.5 = total amount of pure acid\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide this over the 45 total liters, and the goal is to arrive at a 40% concentration.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(amount of pure acid)/(total) = concentration \n" ); document.write( "(0.90x+4.5)/(45) = 0.40 \n" ); document.write( "0.90x+4.5 = 45*0.40 \n" ); document.write( "0.90x+4.5 = 18 \n" ); document.write( "0.90x = 18-4.5 \n" ); document.write( "0.90x = 13.5 \n" ); document.write( "x = 13.5/0.90 \n" ); document.write( "x = 15 \n" ); document.write( "which leads to \n" ); document.write( "45-x = 45-15 = 30\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, we need 15 liters of pure acid to add to the 30 liters of the 10% acid solution.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In other words, we need 15 liters of batch A and 30 liters of batch B.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Method 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Batch A = 100% acid \n" ); document.write( "Batch B = 10% acid \n" ); document.write( "target solution = 40%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Gap from target to 100% is 60% \n" ); document.write( "Gap from 10% to target is 30%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The ratio of 60% to 30% is 60:30 = 2:1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Meaning we'll need twice as much one batch compared to the other.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2:1 scales up to 2k:1k for some positive real number k. \n" ); document.write( "2k+1k = 45 \n" ); document.write( "3k = 45 \n" ); document.write( "k = 45/3 \n" ); document.write( "k = 15 \n" ); document.write( "So 2k = 2*15 = 30\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The amounts for batches A and B are 15 and 30. The order isn't clear just yet.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If we had 30 L of batch A, then we'll have 15*0.10 = 1.5 L of pure acid from batch B. \n" ); document.write( "The total amount of pure acid would be 30+1.5 = 31.5 \n" ); document.write( "But notice that 31.5/45 = 0.70 = 70% which isn't the 40% target we're after.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If we had 15 L of batch A, then we'll have 30*0.10 = 3 L of pure acid from batch B. \n" ); document.write( "15+3 = 18 L of pure acid total out of 45 L total \n" ); document.write( "18/45 = 0.40 = 40% \n" ); document.write( "We've reached the goal.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For more information, search out \"Alligation Method Pharmacy\". \n" ); document.write( "The spelling of \"Alligation\" is correct. There isn't an \"e\" but an \"i\" instead. Think \"alligator\". \n" ); document.write( "It's unfortunate the two words sound identical, and are spelled almost the same.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here is a useful calculator \n" ); document.write( "https://calculatormaths.com/alligation-calculator \n" ); document.write( " \n" ); document.write( " |