document.write( "Question 1204463: Pure acid is to be added to a 10% acid solution to obtain 45L of a 40% acid solution.
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Algebra.Com's Answer #840730 by josgarithmetic(39617) $\"\"$ $\"About$

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If use v liters of the pure 100% acid, then use 45-v liters of the 10% acid.\r
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\n" ); document.write( "\n" ); document.write( "To account for the amount of pure acid for the mixture,
\n" ); document.write( " $\"v%2B0.10%2845-v%29=0.40%2A45\"$
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\n" ); document.write( " $\"v%2B%280.1%29%2845%29-0.1v=%280.4%29%2845%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"%281-0.1%29v=0.4%2A45-0.1%2A45\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"v=45%28%280.4-0.1%29%2F%281-0.1%29%29\"$ ----------think about this expression a bit, before continuing...\r
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\n" ); document.write( "\n" ); document.write( " $\"v=45%281%2F3%29\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"highlight%28v=15%29\"$ ------and you know the quantity for the 10% acid is 30 L.
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