document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1204453>Question 1204453</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Shantel has  <BR>\n" );
document.write( "$<BR>\n" );
document.write( "3.60<BR>\n" );
document.write( "  in dimes and nickles in her car. The number of nickles is three more than the number of dimes. How many of each type of coin does she have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #840714 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13216)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=840714\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Probably a formal algebraic solution, like the one shown by tutor @ikleyn, was wanted.  But you can get good mental exercise solving the problem informally, using logical reasoning and mental arithmetic.<br><BR>\n" );
document.write( "The number of nickels is 3 more than the number of dimes, and the total value is $3.60.<br><BR>\n" );
document.write( "Set aside those 3 \"extra\" nickels, worth $0.15, leaving a value of $3.45 for the remaining coins.<br><BR>\n" );
document.write( "Those remaining coins are equal numbers of nickels and dimes.  The value of one nickel and one dime is $0.15. $3.45/$0.15 = 23, so the remaining coins are 23 nickels and 23 dimes.<br><BR>\n" );
document.write( "Now add back in the other 3 nickels, making 26 nickels and 23 dimes.<br><BR>\n" );
document.write( "ANSWER: 26 nickels and 23 dimes<br><BR>\n" );
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