document.write( "Question 1204447: Two bicyclists are 25 mi apart and are traveling toward each other. One cyclist is traveling at 2/3 the rate of the other cyclist. The cyclists pass each other in 2 h. Find the rate of each cyclist. \n" ); document.write( "
Algebra.Com's Answer #840701 by Edwin McCravy(20060)\"\" \"About 
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document.write( "She did it by adding the two distances they rode together to equal\r\n" );
document.write( "the total distance of 25 miles.\r\n" );
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document.write( "Another way is the approach rate method.  That method is to add the \r\n" );
document.write( "two rates and that gives the rate at which the distance between them \r\n" );
document.write( "is shrinking to zero. That is, the total 25 miles distance between \r\n" );
document.write( "them reduces to zero when they come together. \r\n" );
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document.write( "Their approach rate is the sum of their rates, so\r\n" );
document.write( "If the faster rate is x, the slower rate is (2/3)x.\r\n" );
document.write( "Their approach rate is the sum of their rates, x+(2/3)x or (5/3)x.\r\n" );
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document.write( "They pass each other is 2 hours.  The distance between them is 25 miles.\r\n" );
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document.write( "Since (rate)(time) = distance,\r\n" );
document.write( "       [(5/3)x](2) = 25 \r\n" );
document.write( "           (10/3)x = 25\r\n" );
document.write( "               10x = 75\r\n" );
document.write( "                 x = 7 1/2 mph = rate of faster biker.\r\n" );
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document.write( "                 (2/3)x = (2/3)(7 1/2) = (15/2)(2/3) = 5 mph = rate of slower\r\n" );
document.write( "biker.\r\n" );
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document.write( "Edwin
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