document.write( "Question 1204427: A man borrows 1,000 and agrees to repay with 10 instalments, each instalment being less than the preceding instalment by 8. Find the his first instalment \n" ); document.write( "

Algebra.Com's Answer #840691 by ikleyn(52794) $\"\"$ $\"About$

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\n" ); document.write( "A man borrows 1,000 and agrees to repay with 10 instalments, each instalment
\n" ); document.write( "being less than the preceding instalment by 8. Find the his first instalment
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document.write( "In this sequence of 10 terms, the in-pair sums of the numbers, equally remoted from the endpoints,\r\n" );
document.write( "are a constant value:  \r\n" );
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document.write( "     =  =  =  = .\r\n" );
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document.write( "Therefore, each in-pair sum is  1000/5 = 200.\r\n" );
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document.write( "So, about the pair  we know that\r\n" );
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document.write( "     = 200\r\n" );
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document.write( "     =   8\r\n" );
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document.write( "From it, it is easy to guess/(to derive) that   = 100 + 8/2 = 104.\r\n" );
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document.write( "Now, the term , , ,   are\r\n" );
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document.write( "    104+8 = 112,  112+8 = 120,  120+8 = 128,  128+8 = 136, respectively.\r\n" );
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document.write( "Thus, the first term (= the first installment) is 136.    ANSWER\r\n" );
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