document.write( "Question 1204428: A man borrows 2,00 and agrees to repay with a total interest of 340 in 12 monthly instalment, each instalment being less than the preceding instalment by 10, What should be his first instalment? \n" ); document.write( "
Algebra.Com's Answer #840689 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "I assume you meant to write 2,000 instead of 2,00\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a = first installment = first term of arithmetic sequence\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n = 12 = number of payments \n" ); document.write( "d = -10 = common difference, since the payment amounts drop by 10 each time.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Sn = sum of first n terms of arithmetic sequence, aka arithmetic progression (AP) \n" ); document.write( "Sn = 2000+340 = 2340 total needs to be paid back\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Sn = (n/2)*(2*a + d(n-1)) \n" ); document.write( "2340 = (12/2)*(2*a - 10(12-1)) \n" ); document.write( "2340 = 6*(2a-110) \n" ); document.write( "2340 = 12a-660 \n" ); document.write( "12a-660 = 2340 \n" ); document.write( "12a = 2340+660 \n" ); document.write( "12a = 3000 \n" ); document.write( "a = 3000/12 \n" ); document.write( "a = 250\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We can use the \"sequence\" command in GeoGebra to generate this arithmetic progression \n" ); document.write( "250, 240, 230, 220, 210, 200, 190, 180, 170, 160, 150, 140 \n" ); document.write( "A spreadsheet is another option.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then add up the values and we should get to 2340 \n" ); document.write( "250+240+230+220+210+200+190+180+170+160+150+140 = 2340 \n" ); document.write( "We have confirmed the answer. \n" ); document.write( "Or a shortcut \n" ); document.write( "(n/2)*(1st term + 12th term) = (12/2)*(250 + 140) = 2340\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 250 \n" ); document.write( " \n" ); document.write( " |