document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1204430>Question 1204430</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man borrows 1,000 and agrees to repay with 10 instalments, each instalment being less than the preceding instalment by 8. Find the his first instalment  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #840681 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=840681\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Here in this problem <BR>\n" );
document.write( "amount to be repaid = 1000  Sn =1000\r<BR>\n" );
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document.write( "number of instalments =10 n=10<BR>\n" );
document.write( "every instalment less by 8 d=-8\r<BR>\n" );
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document.write( "Sn=n/2(2a+(n-1)d\r<BR>\n" );
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document.write( "Plug and solve for a\r<BR>\n" );
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document.write( "1000 =10/5 (2*a+(10-1)*-8\r<BR>\n" );
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document.write( "1000/5 = 2*a-72\r<BR>\n" );
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document.write( "200= 2a-72\r<BR>\n" );
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document.write( "200+72=2a\r<BR>\n" );
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document.write( "272/2= a<BR>\n" );
document.write( "a=136<BR>\n" );
document.write( "The first installment is 136.<BR>\n" );
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