document.write( "Question 115476: x+x+x+1=201
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document.write( " 3x+1=201
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document.write( "The sum of the first number is 66, the second 67, and the third number is 68. \r
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document.write( "Is this correct and please explain ! \n" );
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Algebra.Com's Answer #84068 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! X+X+X+1=201 \n" ); document.write( "3X=201-1 \n" ); document.write( "3X=200 \n" ); document.write( "X=66.67 ANSWER. \n" ); document.write( "------------------------------------------------ \n" ); document.write( "IF YOU MEANT: \n" ); document.write( "WHAT 3 COSECUTIVE NUMBERS TOTAL 201? \n" ); document.write( "THEN: \n" ); document.write( "X+(X+1)+(X+2)=201 \n" ); document.write( "3X+3=201 \n" ); document.write( "3X=201-3 \n" ); document.write( "3X=198 \n" ); document.write( "X=66 \n" ); document.write( "X+1=67 \n" ); document.write( "X+2=68 \n" ); document.write( " |