document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=115401>Question 115401</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Am trying to answer homework questions, and I cant seem to get these log questions right, please help???\r<BR>\n" );
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document.write( "1. if log(a)2= .301   , log(a)6= .778   , log(a)7= .845 then what is log(a)42?\r<BR>\n" );
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document.write( "(a. .067, b. .065741, c.1.079 , d.,1.623)  I am leaning towards 1.623, but I am not 100% sure. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #84066 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=84066\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. if log(a)2= .301   , log(a)6= .778   , log(a)7= .845 then what is log(a)42?<BR>\n" );
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document.write( "Think about the rules of logs: when you multiply, the logs of the numbers are added to obtain the log of the product of the two numbers<BR>\n" );
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document.write( "6 * 7 = 42<BR>\n" );
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document.write( "Therefore if you add the logs of 6 and 7 it should = the log of 42, right? </SPAN>\n" );
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