document.write( "Question 1204414: The effectiveness of a blood-pressure drug is being investigated. An experimenter finds that, on average, the reduction in systolic blood pressure is 54.2 for a sample of size 362 and standard deviation 17.4.\r
\n" ); document.write( "\n" ); document.write( "Estimate how much the drug will lower a typical patient's systolic blood pressure (using a 95% confidence level).\r
\n" ); document.write( "\n" ); document.write( "Enter your answer as a tri-linear inequality accurate to one decimal place (because the sample statistics are reported accurate to one decimal place).
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Algebra.Com's Answer #840659 by Theo(13342)\"\" \"About 
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sample size is 362.
\n" ); document.write( "sample mean is 54.2
\n" ); document.write( "sample stansard deviation is 17.4
\n" ); document.write( "using the t-score, critical t-score with 361 degrees of freedom (sample size minus 1) is equal to plus or minus 1.9666.
\n" ); document.write( "t-score formula is t = (x-m)/s
\n" ); document.write( "t is the t-score
\n" ); document.write( "x is the critical mean
\n" ); document.write( "m is the sample mean
\n" ); document.write( "s is the standard error\r
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\n" ); document.write( "\n" ); document.write( "standard error = standard deviation / sqrt(sample size) = 17.4 / sqrt(362) = .9145.
\n" ); document.write( "on the high side, t=(x-m)/s becomes 1.9666 = (x-54.2)/.9145.
\n" ); document.write( "solve for x to get x = 1.9666 * .9145 + 54.2 = 55.9985
\n" ); document.write( "on the low side, t = (x-m)/s becomes -1.9666 = (x-54.2)/.9245.
\n" ); document.write( "solve for x to get x = -1.9666 * .9145 + 54.2 = 52.4015.
\n" ); document.write( "round to 1 decimal place to get:
\n" ); document.write( "the 95% confidence interval is between 52.4 and 56 points at 95% confidence level.
\n" ); document.write( "your tri-linear equality would be 52.4 <= x <= 56.
\n" ); document.write( "since the variable is continuous, then some sticklers will say 52.4 < x < 56 bcause the value can never be exactly a specific value.\r
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