document.write( "Question 1186342: At exactly 12 o’clock noon the hour hand of a clock begins to move at twice its
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document.write( "normal speed, and the minute hand begins to move backward at half its normal
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document.write( "speed. When the two hands next coincide, what will be the correct time? \n" );
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Algebra.Com's Answer #840640 by ikleyn(52794)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "At exactly 12 o'clock noon the hour hand of a clock begins to move at twice its normal speed, \n" ); document.write( "and the minute hand begins to move backward at half its normal speed. \n" ); document.write( "When the two hands next coincide, what will be the correct time? \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "The normal angular speed of the hour hand is 360/12 = 30 degrees per hour;\r\n" ); document.write( "so, its doubled speed is 60 degree per hour.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The normal angular speed of the minute hand is 360 degrees per hour;\r\n" ); document.write( "so, half of its speed is 180 degrees per hour.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Thus, in this problem, the hour hand rotates anti-clockwise at 60 degrees per hour; \r\n" ); document.write( " the minute hand rotates clockwise at 180 degrees per hour.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "They approach each other at the rate of (60+180) = 240 degrees per hour.\r\n" ); document.write( "\r\n" ); document.write( "So, they coincide next time in 360/240 = 1\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |