document.write( "Question 115517: Find the horizontal and vertical asymptotes of the following. Type “none” if the function does not have an asymptote.\r
\n" ); document.write( "\n" ); document.write( "f(x)=(2x-3)/(x^2+2)
\n" ); document.write( "

Algebra.Com's Answer #84064 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
a)\r
\n" ); document.write( "\n" ); document.write( "Horizontal Asymptote:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Since the degree of the numerator (which is \"1\") is less than the degree of the denominator (which is \"2\"), the horizontal asymptote is always \"y=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the horizontal asymptote is \"y=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Vertical Asymptote:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "To find the vertical aysmptote(s), set the denominator equal to zero:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B2=0\" Set the denominator equal to zero\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2=-2\" Subtract 2 from both sides\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x=sqrt%28-2%29\" Take the square root of both sides\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Since you cannot take the square root of a negative number, the answer is not a real number. So in this case, there are no vertical asymptotes
\n" ); document.write( "
\n" );