document.write( "Question 115517: Find the horizontal and vertical asymptotes of the following. Type “none” if the function does not have an asymptote.\r
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document.write( "f(x)=(2x-3)/(x^2+2) \n" );
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Algebra.Com's Answer #84064 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! a)\r \n" ); document.write( "\n" ); document.write( "Horizontal Asymptote:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since the degree of the numerator (which is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the horizontal asymptote is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Vertical Asymptote:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To find the vertical aysmptote(s), set the denominator equal to zero:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since you cannot take the square root of a negative number, the answer is not a real number. So in this case, there are no vertical asymptotes \n" ); document.write( " |