document.write( "Question 1204408: The average temperature of a fictious town is given by the equation: f(x) = 20 sin (π/13x) + 2 where x represents the number of weeks since beggining of year. During the course of the year for how many weeks was the average temperature higher than 15° celcius \n" ); document.write( "
Algebra.Com's Answer #840633 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "1 year = 52 weeks approximately\r
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\n" ); document.write( "\n" ); document.write( "Desmos Graph
\n" ); document.write( "https://www.desmos.com/calculator/4eidoto8nc\r
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\n" ); document.write( "\n" ); document.write( "The Desmos graph shows the sine function f(x) = 20*sin( (pi/13)x ) + 2, along with the horizontal line y = 15.\r
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\n" ); document.write( "\n" ); document.write( "On the domain 0 < x < 52, the intersection points are approximately:
\n" ); document.write( "A = (2.928,15)
\n" ); document.write( "B = (10.072,15)
\n" ); document.write( "C = (28.928,15)
\n" ); document.write( "D = (36.072,15)\r
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\n" ); document.write( "\n" ); document.write( "The gap from A to B is one chunk of time when the temperature is above 15 degrees Celsius.
\n" ); document.write( "10.072-2.928 = 7.144, which is about 7 weeks.\r
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\n" ); document.write( "\n" ); document.write( "The gap from C to D is another chunk of time when the temperature is above 15 degrees Celsius.
\n" ); document.write( "36.072-28.928 = 7.144, also about 7 weeks.\r
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\n" ); document.write( "\n" ); document.write( "The total would then be roughly 7+7 = 14 weeks out of the 52 week timespan.\r
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\n" ); document.write( "\n" ); document.write( "Edit: The student has mentioned the textbook's answer is 14.29
\n" ); document.write( "This is because 2*7.144 = 14.288 which rounds to 14.29
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