document.write( "Question 1204405: A survey of 500 people was conducted to determine how many people own a pet, and how many people own a car. The results showed that 300 people own a pet, 150 people own a car, and 100 people own both a pet and a car. What is the probability that a randomly selected person owns a pet or a car?
\n" ); document.write( "P(A or B) = P(A) + P(B) - P(A and B) where P(A) is the probability of owning a pet, P(B) is the probability of owning a car, and P(A and B) is the probability of owning both a pet and a car. Is the answer .70 or .72?\r
\n" ); document.write( "\n" ); document.write( "300/500 + 150/500 - 100/500 = 350/500 = 7/10 = .70\r
\n" ); document.write( "\n" ); document.write( "300/500 = .60 ; 150/500 = .30 ; (1 - (.60 + .30) = .10 own both a pet a and car\r
\n" ); document.write( "\n" ); document.write( ".60 + .30 - (.60 * .30)
\n" ); document.write( "0.90 - 0.18 = 0.72
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Algebra.Com's Answer #840622 by ikleyn(52776) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Do not confuse yourself - and do not try to confuse other people. \r
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document.write( "P(car or pet) = P(car) + P(pet) - P(BOTH) =  +  -  =   =  =  =  = 0.7.    ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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document.write( "    Do not try to introduce 0.6*0.3 = 0.18  without necessity, \r\n" );
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document.write( "         since it relates to INDEPENDENT events ONLY, \r\n" );
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document.write( "           which is NOT the CASE in this problem.\r\n" );
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