document.write( "Question 1204389: Find the general solutions (in radians) of the following equations:
\n" ); document.write( " 3 cot (3𝑥 +𝜋/4) = √3
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Algebra.Com's Answer #840609 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"3cot%283x+%2Bpi%2F4%29+=+sqrt%283%29\"\r
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\n" ); document.write( "\n" ); document.write( " \"cot+%283x+%2Bpi%2F4%29+=+sqrt%283%29%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "since \"cot%28x%29=+sqrt%283%29%2F3+\"=> \"x+=pi%2A+n+%2Bpi%2F3\",\"+n+\"element \"Z\"\r
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\n" ); document.write( "\n" ); document.write( "then \r
\n" ); document.write( "\n" ); document.write( "\"3x+%2Bpi%2F4+=pi%2A+n+%2Bpi%2F3\".....solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"3x+=pi%2A+n+%2Bpi%2F3-pi%2F4+\"\r
\n" ); document.write( "\n" ); document.write( "\"3x+=pi%2An+%2B+pi%2F12\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=pi%2An+%2F3%2B+%28pi%2F12%29%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=pi%2An+%2F3%2B+pi%2F36\"\r
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