document.write( "Question 115515: Consider the function f(x)=x^2+6x-2. \r
\n" ); document.write( "\n" ); document.write( "a) Find h, the x-coordinate of the vertex of this parabola.
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Algebra.Com's Answer #84060 by jim_thompson5910(35256)\"\" \"About 
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a)\r
\n" ); document.write( "\n" ); document.write( "To find h, we first need to find the axis of symmetry (ie the x-coordinate of the vertex)\r
\n" ); document.write( "\n" ); document.write( "To find the axis of symmetry, use this formula:\r
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\n" ); document.write( "\n" ); document.write( "\"x=-b%2F%282a%29\"\r
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\n" ); document.write( "\n" ); document.write( "From the equation \"y=x%5E2%2B6x-2\" we can see that a=1 and b=6\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-6%29%2F%282%2A1%29\" Plug in b=6 and a=1\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-6%29%2F2\" Multiply 2 and 1 to get 2\r
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\n" ); document.write( "\n" ); document.write( "\"x=-3\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "So the axis of symmetry is \"x=-3\" which means \"h=-3\"\r
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\n" ); document.write( "\n" ); document.write( "Lets evaluate \"f%28-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29=x%5E2%2B6x-2\" Start with the given polynomial\r
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\n" ); document.write( "\n" ); document.write( "\"f%28-3%29=%28-3%29%5E2%2B6%28-3%29-2\" Plug in \"x=-3\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%28-3%29=%289%29%2B6%28-3%29-2\" Raise -3 to the second power to get 9\r
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\n" ); document.write( "\n" ); document.write( "\"f%28-3%29=%289%29%2B-18-2\" Multiply 6 by -3 to get -18\r
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\n" ); document.write( "\n" ); document.write( "\"f%28-3%29=-11\" Now combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So the vertex is (-3,-11)
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