document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1204372>Question 1204372</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the second and fifth terms of an G.P are 6 and 48 respectively, find the 10th term of the G.P </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #840574 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=840574\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the second and fifth terms of an G.P are 6 and 48 respectively, find the 10th term of the G.P\r<BR>\n" );
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document.write( "nth. term of GP =  an = ar^(n-1)\r<BR>\n" );
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document.write( "a5 = 48 - a^(5-1)<BR>\n" );
document.write( "-> 48 = ar^4---------------(1)\r<BR>\n" );
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document.write( "Similarly<BR>\n" );
document.write( "a2 = 6= a^(2-1)\r<BR>\n" );
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document.write( "ar =6------------------------(2)<BR>\n" );
document.write( "divide (2) by(1)\r<BR>\n" );
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document.write( "48/6 = ar^4/ar<BR>\n" );
document.write( "r^3=8<BR>\n" );
document.write( "r=2\r<BR>\n" );
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document.write( "ar =6\r<BR>\n" );
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document.write( "but r=2<BR>\n" );
document.write( "2a=6<BR>\n" );
document.write( "a=3\r<BR>\n" );
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document.write( "a10 = ar^9\r<BR>\n" );
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document.write( "a10 = 3*2*9 =1536\r<BR>\n" );
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document.write( "10th term of the geometric progression is 1536.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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