document.write( "Question 1204344: When \"ax%5E3-x%5E2%2B3x%2Bb\" is divided by x - 2, the remainder is 59. When it is divided by x + 1, the remainder is - 1. Find the values of a and b. \n" ); document.write( "
Algebra.Com's Answer #840524 by math_tutor2020(3817)\"\" \"About 
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Remainder Theorem:
\n" ); document.write( "If P(x) is divided over (x-k), then P(k) is the remainder.\r
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\n" ); document.write( "\n" ); document.write( "f(x) = ax^3 - x^2 + 3x + b
\n" ); document.write( "f(2) = a(2)^3 - (2)^2 + 3(2) + b
\n" ); document.write( "f(2) = 8a + b + 2
\n" ); document.write( "f(2) = 59 because of the remainder theorem
\n" ); document.write( "8a + b + 2 = 59
\n" ); document.write( "b = 59-2-8a
\n" ); document.write( "b = 57-8a\r
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\n" ); document.write( "\n" ); document.write( "f(x) = ax^3 - x^2 + 3x + b
\n" ); document.write( "f(-1) = a(-1)^3 - (-1)^2 + 3(-1) + b
\n" ); document.write( "f(-1) = -a + b - 4
\n" ); document.write( "f(-1) = -1 because of the remainder theorem
\n" ); document.write( "-a + b - 4 = -1
\n" ); document.write( "-a + (57-8a) - 4 = -1
\n" ); document.write( "-9a + 53 = -1
\n" ); document.write( "-9a = -1-53
\n" ); document.write( "-9a = -54
\n" ); document.write( "a = -54/(-9)
\n" ); document.write( "a = 6\r
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\n" ); document.write( "\n" ); document.write( "Then,
\n" ); document.write( "b = 57-8a
\n" ); document.write( "b = 57 - 8*6
\n" ); document.write( "b = 57 - 48
\n" ); document.write( "b = 9
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