document.write( "Question 1204323: A probability distribution has a mean of 40 and a standard deviation of 8. Use Chebyshev's inequality to find the minimum probability that an outcome is between 0 and 80. (Round your answer to four decimal places.)
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Algebra.Com's Answer #840494 by MathLover1(20849) $\"\"$ $\"About$

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\n" ); document.write( " $\"P%280+%3C=x+%3C=80%29\"$ , where $\"mu+=+40\"$ , $\"sigma+=+8\"$ is\r
\n" ); document.write( "\n" ); document.write( " $\"P%280+%3C=x+%3C=80%29=erf%285%2Fsqrt%282%29%29=+0.9999\"$ \r
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