document.write( "Question 1204305: Determine whether the binomial (3x - 2) is a factor of the polynomial \"3x%5E3-14x%5E2%2B26x-12\"\r
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Algebra.Com's Answer #840470 by ikleyn(52786)\"\" \"About 
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\n" ); document.write( "Determine whether the binomial (3x-2) is a factor of the polynomial \"3x%5E3-14x%5E2%2B26x-12\".
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\n" ); document.write( "\n" ); document.write( "Alternatively to other methods, you can factor the polynomial explicitly,
\n" ); document.write( "using the grouping and re-grouping method and applying it step by step.\r
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\n" ); document.write( "\n" ); document.write( "This is made easier by the fact that the basic binomial 3x-2 is just given to work with it.\r
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\n" ); document.write( "\n" ); document.write( "3x^3 - 14x^2 + 26x - 12 = group and re-group the terms step by step = (3x^2 - 2x^2) - 12x^2 + 26x - 12 = \r
\n" ); document.write( "\n" ); document.write( "= x^2*(3x-2) - (12x^2 -26x) - 12 = x^2*(3x-2) - (12x^2 - 8x) - 8x + 26x - 12 = x^2*(3x-2) - 4x(3x-2) + (18x-12) = \r
\n" ); document.write( "\n" ); document.write( "= x^2*(3x-2) - 4x(3x-2) + 6(3x-2) = take off the common factor (3x-2) = (3x-2)*(x^2 - 4x + 6).\r
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\n" ); document.write( "\n" ); document.write( "The last formula shows explicitly that (3x-2) is the factor.
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