document.write( "Question 1204301: How much pure acid should be mixed with 4 gallons of a 60% acid solution in order to get 80% acid​ solution? \n" ); document.write( "
Algebra.Com's Answer #840461 by mananth(16946)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "How much pure acid should be mixed with 4 gallons of a 60% acid solution in order to get 80% acid​ solution?\r
\n" ); document.write( "\n" ); document.write( "Pure acid 100%
\n" ); document.write( "Let quantity to be added be x gallons to get 80% acid\r
\n" ); document.write( "\n" ); document.write( "available acid 60% 4 gallons\r
\n" ); document.write( "\n" ); document.write( "Required 80% acid . Volume after mixing will be (4+x) gallons\r
\n" ); document.write( "\n" ); document.write( "100*x+60*4= (x+4) *80\r
\n" ); document.write( "\n" ); document.write( "100x+240 = 80x+320\r
\n" ); document.write( "\n" ); document.write( "20x = 80\r
\n" ); document.write( "\n" ); document.write( "x=4 \r
\n" ); document.write( "\n" ); document.write( " mix 4 gallons of pure acid with the 4 gallons of the 60% acid solution to get 80% acid solution.
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