document.write( "Question 115477This question is from textbook algebra 1
\n" ); document.write( ": A two-digit number is five times its units digit. if the digits are reversed the resulting number is 27 more than the original number, find the original number? \n" ); document.write( "
Algebra.Com's Answer #84041 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Let x = 10's digit and y = the units digit
\n" ); document.write( ":
\n" ); document.write( "Write an equation for what it says, simplify as much as you can:
\n" ); document.write( "\"A two-digit number is five times its units digit.\"
\n" ); document.write( "10x + y = 5y
\n" ); document.write( "10x = 5y - y
\n" ); document.write( "10x = 4y
\n" ); document.write( "x = \"%284y%29%2F10\"
\n" ); document.write( "x = .4y
\n" ); document.write( ":
\n" ); document.write( "\"if the digits are reversed the resulting number is 27 more than the original number\"
\n" ); document.write( "10y + x = 10x + y + 27
\n" ); document.write( ":
\n" ); document.write( "10y - y = 10x - x + 27
\n" ); document.write( ":
\n" ); document.write( "9y = 9x + 27
\n" ); document.write( ":
\n" ); document.write( "Simplify, divide by 9:
\n" ); document.write( "y - x + 3
\n" ); document.write( ":
\n" ); document.write( "Substitute .4y for x in the above equation, find y
\n" ); document.write( "y = .4y + 3
\n" ); document.write( "y - .4y = 3
\n" ); document.write( ".6y = 3
\n" ); document.write( "y = 3/.6
\n" ); document.write( "y = 5
\n" ); document.write( ":
\n" ); document.write( "x = .4y
\n" ); document.write( "x = .4(5)
\n" ); document.write( "x = 2
\n" ); document.write( ":
\n" ); document.write( "Our original two digit number is 25:
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check our solution in the statement:
\n" ); document.write( " \"if the digits are reversed the resulting number is 27 more than the original number, \"
\n" ); document.write( "52 = 25 + 27; confirms our solution
\n" ); document.write( ":
\n" ); document.write( "Did this make sense to you? Not that hard, right? \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );