document.write( "Question 1204250: Let x be a real number such that 625^x=64 Then
\n" ); document.write( "125x=a√b. What are a and b?
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Algebra.Com's Answer #840380 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Let \"x+\"be a real number such that \"625%5Ex=64+\"\r
\n" ); document.write( "\n" ); document.write( "Then \"125%5Ex=a%2Asqrt%28b%29\" What are \"a+\"and \"b\"?\r
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\n" ); document.write( "\n" ); document.write( "We have the equation \"625%5Ex+=+64\"\r
\n" ); document.write( "\n" ); document.write( "To simplify the equation, we can express both sides with the same base. We know that \"625\" can be expressed as \"5%5E4\" and \"64\" can be expressed as \"2%5E6\".\r
\n" ); document.write( "\n" ); document.write( "Rewriting the equation, we have \r
\n" ); document.write( "\n" ); document.write( "\"%285%5E4%29%5Ex+=+2%5E6\"\r
\n" ); document.write( "\n" ); document.write( "Using the property of exponents, we can simplify further:\r
\n" ); document.write( "\n" ); document.write( "\"5%5E%284x%29+=+2%5E6\"\r
\n" ); document.write( "\n" ); document.write( "To find \"x\", we need to equate the exponents:\r
\n" ); document.write( "\n" ); document.write( "\"4x+=+6\"\r
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\n" ); document.write( "\n" ); document.write( "Now, solving for\"+x\":\r
\n" ); document.write( "\n" ); document.write( "\"x+=+6%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "Now, we can calculate the value of \"125%5Ex\" using the value of \"x+\"we found:\r
\n" ); document.write( "\n" ); document.write( "\"125%5E%286%2F4%29=125%5E%283%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "since \"125=5%5E3\", we have \"%285%5E3%29%5E%283%2F2%29=5%5E%283%283%2F2%29%29=5%5E%289%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "then\r
\n" ); document.write( "\n" ); document.write( "\"125%5Ex+=+sqrt%285%5E9%29\"\r
\n" ); document.write( "\n" ); document.write( "since \"sqrt%285%5E9%29=sqrt%28%285%5E4%29%5E2%2A5%29=5%5E4%2Asqrt%285%29=625sqrt%285%29\", then\r
\n" ); document.write( "\n" ); document.write( "\"125%5Ex+=+625sqrt%285%29\"\r
\n" ); document.write( "\n" ); document.write( "so, comparing to \"125%5Ex=a%2Asqrt%28b%29\", we have\r
\n" ); document.write( "\n" ); document.write( "\"a=625\"\r
\n" ); document.write( "\n" ); document.write( "\"b=5\"\r
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