document.write( "Question 1204249: Let f(x) = 1/(1 + 2/(1 + 3/x). There are three real numbers x that are not in the domain of f(x). What is the sum of those three numbers? \n" ); document.write( "
Algebra.Com's Answer #840377 by MathLover1(20850)\"\" \"About 
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\"f%28x%29+=+1%2F%281+%2B+2%2F%281+%2B+3%2Fx%29%29\".....\"x\" is in denominator, so \"x%3C%3E0\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29+=+1%2F%281+%2B+2%2F%28%28x+%2B+3%29%2Fx%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29+=+1%2F%281+%2B+1%2F%281+%2B+2x%2F%28x+%2B+3%29%29%29\".....\"x%2B3\" is in denominator, so \"x%3C%3E-3\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29+=+1%2F%28%283%28x+%2B+1%29%29%2F%28x+%2B+3%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29+=+%28x+%2B+3%29%2F%283+%28x+%2B+1%29%29\"....\"x%2B1\" is in denominator, so \"x%3C%3E-1\"\r
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\n" ); document.write( "\n" ); document.write( "domain:\r
\n" ); document.write( "\n" ); document.write( "{ \"x\" element \"R+\": \"x%3C%3E-3\" and \"x%3C%3E-1\" and \"x%3C%3E0\" }\r
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\n" ); document.write( "\n" ); document.write( "interval:\r
\n" ); document.write( "\n" ); document.write( "(\"-infinity\",\"-3\") U (\"-3\",\"-1\") U (\"-1\",\"0\") U (\"0\",\"infinity\")\r
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\n" ); document.write( "\n" ); document.write( "the sum of those three numbers is:\r
\n" ); document.write( "\n" ); document.write( "\"-3%2B%28-1%29%2B0=-4\"\r
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