document.write( "Question 1204211: There is a right-angled triangle (height=4x, base=x) and a rectangle (length=5x-2, width=x-1). all measurements are in centimeters. the area of the rectangle is greater than the area of the triangle. find the set of possible values of x. step-by-step explanation needed please \n" ); document.write( "
Algebra.Com's Answer #840305 by mananth(16946)\"\" \"About 
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There is a right-angled triangle (height=4x, base=x) and a rectangle (length=5x-2, width=x-1). all measurements are in centimeters. the area of the rectangle is greater than the area of the triangle. find the set of possible values of x. step-by-step explanation needed please\r
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\n" ); document.write( "\n" ); document.write( "There is a right-angled triangle (height=4x, base=x)\r
\n" ); document.write( "\n" ); document.write( "Area of triangle 1/2 * 2x*x = 2x^2\r
\n" ); document.write( "\n" ); document.write( " a rectangle (length=5x-2, width=x-1).\r
\n" ); document.write( "\n" ); document.write( "Area of rectangle = L*W =(5x-2)(x-1)
\n" ); document.write( "= 5x^2-7x+2\r
\n" ); document.write( "\n" ); document.write( "5x^2-7x+2 >2x^2\r
\n" ); document.write( "\n" ); document.write( "3x^2-7x+2>0\r
\n" ); document.write( "\n" ); document.write( "3x^2-6x-x+2>0\r
\n" ); document.write( "\n" ); document.write( "3x(x-2)-1(x-2)>0\r
\n" ); document.write( "\n" ); document.write( "(x-2)(3x-1)>0\r
\n" ); document.write( "\n" ); document.write( "either (x-2)>0 or 3x-1>0\r
\n" ); document.write( "\n" ); document.write( "x>2 or x>1/3\r
\n" ); document.write( "\n" ); document.write( "x>2 \r
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