document.write( "Question 1204205: Thomas has $6000 invested among a checking account paying 2% annual interest, a savings account paying 5% annual interest, and a bond paying 7% annual interest. He earns $355 in annual interest and he has $2300 less invested in his savings account than in his bond. How much does he have invested in each account? \n" ); document.write( "
Algebra.Com's Answer #840303 by mananth(16946)\"\" \"About 
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Thomas has $6000 invested among a checking account paying 2% annual interest, a savings account paying 5% annual interest, and a bond paying 7% annual interest. He earns $355 in annual interest and he has $2300 less invested in his savings account than in his bond. How much does he have invested in each account?\r
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\n" ); document.write( "\n" ); document.write( "Thomas has invested in a checking account paying 2% annual interest, Let amount be $x\r
\n" ); document.write( "\n" ); document.write( " A savings account paying 5% annual interest, let investment be $y\r
\n" ); document.write( "\n" ); document.write( "a bond paying 7% annual interest. Let investment be $z\r
\n" ); document.write( "\n" ); document.write( "x+y+z=6000 ----------------------(1)\r
\n" ); document.write( "\n" ); document.write( "He earns $355 in annual interest\r
\n" ); document.write( "\n" ); document.write( "0.02x+0.05y+0.07z = 355-----------------(2)\r
\n" ); document.write( "\n" ); document.write( "he has $2300 less invested in his savings account than in his bond.\r
\n" ); document.write( "\n" ); document.write( "z-2300 =y\r
\n" ); document.write( "\n" ); document.write( "0.02x+0.05y+0.07z= 355 From (2)\r
\n" ); document.write( "\n" ); document.write( "0.02x+0.05(z-2300)+0.07z =355 (substitute y)\r
\n" ); document.write( "\n" ); document.write( "0.02x+ 0.05z -115+0.07z=355\r
\n" ); document.write( "\n" ); document.write( "0.02x+0.12z = 470-----------------------(3)\r
\n" ); document.write( "\n" ); document.write( "multiply by 100\r
\n" ); document.write( "\n" ); document.write( "2x +12z = 47000-------------------(4)\r
\n" ); document.write( "\n" ); document.write( "x+y+z=6000
\n" ); document.write( "substitute z-2300=y\r
\n" ); document.write( "\n" ); document.write( "x+z-2300 +z = 6000\r
\n" ); document.write( "\n" ); document.write( "x+2z = 8300 -------------------(5)\r
\n" ); document.write( "\n" ); document.write( "Solve (4) &(5)\r
\n" ); document.write( "\n" ); document.write( "2x +12z = 47000
\n" ); document.write( "x+2z = 8300 multiply by 2 and subtract\r
\n" ); document.write( "\n" ); document.write( "2x+4z=16600\r
\n" ); document.write( "\n" ); document.write( "8z = 30400
\n" ); document.write( "z= 3800\r
\n" ); document.write( "\n" ); document.write( "y= z-2300
\n" ); document.write( "3800-2300 = 1500\r
\n" ); document.write( "\n" ); document.write( "x= 6000-3800-1500 =700\r
\n" ); document.write( "\n" ); document.write( "Thomas has $700 invested in the checking account, $1500 in the savings account, and $3800 in the bond.\r
\n" ); document.write( "\n" ); document.write( "CHECK\r
\n" ); document.write( "\n" ); document.write( "700*2%+1500*5%+3800*7%= 355\r
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