document.write( "Question 1204196: The area of a rectangle is 54 cm². Its length and breadth are reduced by 5 cm and 2 cm, respectively, so as to become a square. Find
\n" ); document.write( "the length of a side of the square.
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Algebra.Com's Answer #840292 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "L = length
\n" ); document.write( "W = width
\n" ); document.write( "L*W = 54\r
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\n" ); document.write( "\n" ); document.write( "L becomes L-5
\n" ); document.write( "W becomes W-2
\n" ); document.write( "At this point, we have a square
\n" ); document.write( "L-5 = W-2
\n" ); document.write( "L = W-2+5
\n" ); document.write( "L = W+3\r
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\n" ); document.write( "\n" ); document.write( "L*W = 54
\n" ); document.write( "(W+3)*W = 54
\n" ); document.write( "W^2+3W = 54
\n" ); document.write( "W^2+3W-54 = 0
\n" ); document.write( "(W+9)(W-6) = 0
\n" ); document.write( "W+9 = 0 or W-6 = 0
\n" ); document.write( "W = -9 or W = 6
\n" ); document.write( "Ignore the negative value of W.
\n" ); document.write( "L = 54/W
\n" ); document.write( "L = 54/6
\n" ); document.write( "L = 9
\n" ); document.write( "The original rectangle is 9 cm by 6 cm.\r
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\n" ); document.write( "\n" ); document.write( "9-5 = 4
\n" ); document.write( "6-2 = 4
\n" ); document.write( "The rectangle turns into a 4 cm by 4 cm square.\r
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\n" ); document.write( "\n" ); document.write( "Answer: 4 cm
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