document.write( "Question 1204187: Suppose a study of the faculty at U.S. medical schools revealed that 33% of the faculty were women and 67% were men. Of the female faculty, 33% were full/associate professors, 49% were assistant professors, and 18% were instructors. Of the male faculty, 51% were full/associate professors, 36% were assistant professors, and 13% were instructors. If a faculty member at a U.S. medical school selected at random held the rank of full/associate professor, what is the probability that the faculty member was female? (Round your answer to two decimal places.) \n" ); document.write( "
Algebra.Com's Answer #840273 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "It's not necessary to make this chart for this one problem, but you \r\n" );
document.write( "could have been given a number of probability questions instead of\r\n" );
document.write( "just this one. Also making the complete chart makes it easier to \r\n" );
document.write( "understand what's going on.\r\n" );
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document.write( "                Female(33%)            Male(67%)\r\n" );
document.write( "Full/Asso.| 33% of 33% = 10.89% | 51% of 67% = 34.17%\r\n" );
document.write( "Asst.     | 49% of 33% = 16.17% | 36% of 67% = 24.12%\r\n" );
document.write( "Inst.     | 18% of 33% =  5.94% | 13% of 67% =  8.71%

\n" ); document.write( "If a faculty member at a U.S. medical school selected at random held
\n" ); document.write( "the rank of full/associate professor, what is the probability that the
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document.write( "P(Female | Full/Asso.) = P(Female AND Full/Asso.)/P(Full/Asso.) =\r\n" );
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document.write( "10.89%/(10.89%+34.17%) = 10.89%/45.06% = 0.241677763 which rounds to 0.24\r\n" );
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document.write( "Edwin
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