document.write( "Question 1204169: Bill\"s age is a year less than twice Jane's age. 5 years ago Bills's age was 3 times Jane's age. Find Bill's age? \n" ); document.write( "
Algebra.Com's Answer #840262 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "I very much disagree with the other tutor when he says solving a problem like this is easier with two unknowns than with one. \n" ); document.write( "Compare the algebra required to solve the problem with his solution using two unknowns to that required in the solution below using one unknown. \n" ); document.write( "Using the information that 5 years ago Bill's age was 3 times Jane's age.... \n" ); document.write( "Let x = Jane's age 5 years ago \n" ); document.write( "Then 3x = Bill's age 5 years ago \n" ); document.write( "Then their ages now are x+5 and 3x+5. \n" ); document.write( "Bill's age now is 1 less than twice Jane's age now: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Their ages 5 years ago were x=4 and 3x=12. \n" ); document.write( "Their ages now are 4+5=9 and 12+5=17. \n" ); document.write( "ANSWER: Bill's age now is 17 \n" ); document.write( " \n" ); document.write( " |