document.write( "Question 1204178: 12 = 1/32 * x ^ (3/2) - 4 \n" ); document.write( "
Algebra.Com's Answer #840247 by Theo(13342)\"\" \"About 
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equation is:\r
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\n" ); document.write( "\n" ); document.write( "1/32 * x ^ (3/2) - 4 = 12
\n" ); document.write( "add 4 to both sides to get:
\n" ); document.write( "1/32 * x ^ (3/2) = 16
\n" ); document.write( "multiply both sides by 32 to get:
\n" ); document.write( "x ^ (3/2) = 16 * 32 = 512
\n" ); document.write( "raise both sides by the power of (2/3) to get:
\n" ); document.write( "(x ^ (3/2)) ^ (2/3) = 512 ^ (2/3)
\n" ); document.write( "simplify to get:
\n" ); document.write( "x ^ ((3/2) * (2/3)) = 512 ^ (2/3)
\n" ); document.write( "simplify further to get:
\n" ); document.write( "x = 512 ^ (2/3)
\n" ); document.write( "solve for x to get:
\n" ); document.write( "x = 64\r
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\n" ); document.write( "\n" ); document.write( "confirm by replacing x with 64 n the original equation to get:
\n" ); document.write( "1/32 * 64 ^ (3/2) - 4 = 12 becomes 12 = 12, confirming the value of x is good.\r
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