document.write( "Question 1204174: The length of a rectangle is twice its width. If the width is reduced by 1 cm and the length is also reduced by 2 cm, the area will be 15cm².
\n" ); document.write( "Find the dimensions of the original rectangle.
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The length of a rectangle is twice its width. If the width is reduced by 1 cm and the length is also reduced by 2 cm, the area will be 15cm².
\n" ); document.write( "Find the dimensions of the original rectangle.\r
\n" ); document.write( "\n" ); document.write( "Let width be x cm
\n" ); document.write( "Length will be 2x cm .\r
\n" ); document.write( "\n" ); document.write( " (I have reduced length also by 1 and not 2)\r
\n" ); document.write( "\n" ); document.write( " If the width is reduced by 1 cm and the length is also reduced by 1 cm, the area will be 15cm².\r
\n" ); document.write( "\n" ); document.write( "(x-1)(2x-1)=15\r
\n" ); document.write( "\n" ); document.write( "2x^2-x-2x+1=15\r
\n" ); document.write( "\n" ); document.write( "2x^2-3x -14=0\r
\n" ); document.write( "\n" ); document.write( "2x^2-7x+4x-14=0\r
\n" ); document.write( "\n" ); document.write( "x(2x-7)+2(2x-7)=0\r
\n" ); document.write( "\n" ); document.write( "(2x-7)(x+2)=0\r
\n" ); document.write( "\n" ); document.write( "x= 7/2 0r -2\r
\n" ); document.write( "\n" ); document.write( "-2 not possible\r
\n" ); document.write( "\n" ); document.write( "x=3.5 = width\r
\n" ); document.write( "\n" ); document.write( "length = 2x = 7 \r
\n" ); document.write( "\n" ); document.write( "Area = 7*3.5 = 24.5 cm^2\r
\n" ); document.write( "\n" ); document.write( "So, the dimensions of the original rectangle are:
\n" ); document.write( "Width (w) = 3.5cm
\n" ); document.write( "Length (l) = 7 cm\r
\n" ); document.write( "\n" ); document.write( "Check\r
\n" ); document.write( "\n" ); document.write( "(7-1)(3.5-1)= 15\r
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