document.write( "Question 1204169: Bill\"s age is a year less than twice Jane's age. 5 years ago Bills's age was 3 times Jane's age. Find Bill's age? \n" ); document.write( "
Algebra.Com's Answer #840240 by Edwin McCravy(20054)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Word problems are much easier to set up using more than one unknown.\r\n" );
document.write( "But some people think it's easier with only one unknown. I'm sure another\r\n" );
document.write( "tutor will show you how to do it with only one unknown, but it's always\r\n" );
document.write( "harder to set up. \r\n" );
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document.write( "Bill\"s age is a year less than twice Jane's age. \r\n" );
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document.write( "\"B+=+2J+-+1\"\r\n" );
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document.write( "5 years ago Bills's age was 3 times Jane's age. \r\n" );
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document.write( "\"B-5+=+3%28J-5%29\"\r\n" );
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document.write( "\"system%28B=2J-1%2CB-5=3%28J-5%29%29\"\r\n" );
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document.write( "Substitute 2J-1 for B in the 2nd equation:\r\n" );
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document.write( "\"%282J-1%29-5=3%28J-5%29\"\r\n" );
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document.write( "\"2J-1-5=3J-15\"\r\n" );
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document.write( "\"2J-6=3J-15\"\r\n" );
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document.write( "\"-J=-9\"\r\n" );
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document.write( "\"J=9\"\r\n" );
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document.write( "Substitute 9 for J in \r\n" );
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document.write( "\"B=2J-1\"\r\n" );
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document.write( "\"B=2%289%29-1\"\r\n" );
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document.write( "\"B=18-1\"\r\n" );
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document.write( "\"B=17\"\r\n" );
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document.write( "Check the words:\r\n" );
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document.write( "Bill\"s age (17) is a year less than twice Jane's age. \r\n" );
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document.write( "Twice Jane's age is 18, and sure enough Bill is a year less.\r\n" );
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document.write( "5 years ago Bills's age (12) was 3 times Jane's age (4),\r\n" );
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document.write( "Sure enough, 12 is 3 times 4.\r\n" );
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document.write( "Edwin
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