document.write( "Question 115431: we have been studying systems of nonlinear equations in two variables.
\n" ); document.write( "Question:
\n" ); document.write( "Solve: x^2-y^2=1 and x^2+y=7\r
\n" ); document.write( "\n" ); document.write( "I started by isolating the y variable on the 2nd problem
\n" ); document.write( " y=7-x^2
\n" ); document.write( "Then I know I need to use addition or substitution method to solve:
\n" ); document.write( "I picked substitution method.
\n" ); document.write( " x^2-(7-x^2)^2=1
\n" ); document.write( " x^2 -(49-14x^2+x^4)=1
\n" ); document.write( " x^2-49+14x^2-x^4=1 changed signs because of negative sign.
\n" ); document.write( " -x^4+15x^2-49=1 combined like terms
\n" ); document.write( " -1 -1
\n" ); document.write( " --------
\n" ); document.write( " -x^4+15x^2-50=0\r
\n" ); document.write( "\n" ); document.write( " 0=x^4-15x^2+50 rewrite for better understanding\r
\n" ); document.write( "\n" ); document.write( "A=x^2 Use this in replacement of x^2\r
\n" ); document.write( "\n" ); document.write( " 0=A^2-15A+50
\n" ); document.write( " (A-10) (A-5) Factor
\n" ); document.write( " A=10 A=5\r
\n" ); document.write( "\n" ); document.write( " Now I place x^2 back in for A
\n" ); document.write( " x^2=10 x^2=5\r
\n" ); document.write( "\n" ); document.write( "This is where I get lost, I know on old problems I would use my radicand/square root symbol
\n" ); document.write( "over each and x would equal a square root ie: x^2=1 x^2=9
\n" ); document.write( " x= +/-1 x= +/-3\r
\n" ); document.write( "\n" ); document.write( " and my answers were: (1,3) (3,1)
\n" ); document.write( " (-1,-3) (-3,-1)\r
\n" ); document.write( "\n" ); document.write( "Please help me finish this problem:) It's been 2 days trying to figure out what I'm doing wrong.
\n" ); document.write( "

Algebra.Com's Answer #84022 by vertciel(183)\"\" \"About 
You can put this solution on YOUR website!
Hello there,\r
\n" ); document.write( "\n" ); document.write( "1. x^2 - y^2 = 1 and x^2 + y = 7 \r
\n" ); document.write( "\n" ); document.write( "The easier method is actually elimination. \r
\n" ); document.write( "\n" ); document.write( "If I subtract both equations, I get:\r
\n" ); document.write( "\n" ); document.write( "-y^2 - y = -6\r
\n" ); document.write( "\n" ); document.write( "-y^2 - y + 6 = 0\r
\n" ); document.write( "\n" ); document.write( "-(y^2 + y - 6)= 0\r
\n" ); document.write( "\n" ); document.write( "-(y + 3)(y - 2) = 0\r
\n" ); document.write( "\n" ); document.write( "y = -3, 2\r
\n" ); document.write( "\n" ); document.write( "Can you take it from here?\r
\n" ); document.write( "\n" ); document.write( "2. -x^4 + 15x^2 - 50 = 0 \r
\n" ); document.write( "\n" ); document.write( "Let y = x^2.\r
\n" ); document.write( "\n" ); document.write( "-y^2 + 15y - 50 = 0\r
\n" ); document.write( "\n" ); document.write( "y = 5, 10\r
\n" ); document.write( "\n" ); document.write( "Since y = x^2, you have the following two equations:\r
\n" ); document.write( "\n" ); document.write( "x^2 = 5 and x^2 = 10\r
\n" ); document.write( "\n" ); document.write( "If you square root both sides, you get \"+x+=+sqrt%285%29+\" and \"+x+=+sqrt%2810%29+\". If you want to check them, plug them into the original equation.\r
\n" ); document.write( "\n" ); document.write( "Hope this helps! Write back for more help! \r
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