document.write( "Question 1204153: EF is bisected by AC at D. Find AC if EF = 2x + 22, AC = 3x-5, and DE = 2x-4. \n" ); document.write( "
Algebra.Com's Answer #840210 by mananth(16946)![]() ![]() You can put this solution on YOUR website! DE + DF = EF\r \n" ); document.write( "\n" ); document.write( "DE=DF\r \n" ); document.write( "\n" ); document.write( "2x - 4 + 2x - 4 = 2x + 22\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4x - 8 = 2x + 22\r \n" ); document.write( "\n" ); document.write( "2x - 8 = 22\r \n" ); document.write( "\n" ); document.write( "2x = 30\r \n" ); document.write( "\n" ); document.write( "(2x)/2 = 30/2\r \n" ); document.write( "\n" ); document.write( "x = 15\r \n" ); document.write( "\n" ); document.write( "we can find the value of AC:\r \n" ); document.write( "\n" ); document.write( "AC = 3x - 5 \n" ); document.write( "AC = 3(15) - 5 \n" ); document.write( "AC = 45 - 5 \n" ); document.write( "AC = 40\r \n" ); document.write( "\n" ); document.write( "So, AC = 40.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |