document.write( "Question 1204153: EF is bisected by AC at D. Find AC if EF = 2x + 22, AC = 3x-5, and DE = 2x-4. \n" ); document.write( "
Algebra.Com's Answer #840209 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "EF is bisected at D, which means EF is split into two equal pieces ED and DF\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "EF = ED+DF \n" ); document.write( "EF = ED+ED \n" ); document.write( "EF = 2*ED \n" ); document.write( "EF = 2*DE\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "EF = 2*DE \n" ); document.write( "2x+22 = 2*(2x-4) \n" ); document.write( "2x+22 = 4x-8 \n" ); document.write( "2x-4x = -8-22 \n" ); document.write( "-2x = -30 \n" ); document.write( "x = -30/(-2) \n" ); document.write( "x = 15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then, \n" ); document.write( "AC = 3x-5 \n" ); document.write( "AC = 3*15-5 \n" ); document.write( "AC = 45-5 \n" ); document.write( "AC = 40 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |