document.write( "Question 1204153: EF is bisected by AC at D. Find AC if EF = 2x + 22, AC = 3x-5, and DE = 2x-4. \n" ); document.write( "
Algebra.Com's Answer #840209 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "EF is bisected at D, which means EF is split into two equal pieces ED and DF\r
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\n" ); document.write( "\n" ); document.write( "EF = ED+DF
\n" ); document.write( "EF = ED+ED
\n" ); document.write( "EF = 2*ED
\n" ); document.write( "EF = 2*DE\r
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\n" ); document.write( "\n" ); document.write( "EF = 2*DE
\n" ); document.write( "2x+22 = 2*(2x-4)
\n" ); document.write( "2x+22 = 4x-8
\n" ); document.write( "2x-4x = -8-22
\n" ); document.write( "-2x = -30
\n" ); document.write( "x = -30/(-2)
\n" ); document.write( "x = 15\r
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\n" ); document.write( "\n" ); document.write( "Then,
\n" ); document.write( "AC = 3x-5
\n" ); document.write( "AC = 3*15-5
\n" ); document.write( "AC = 45-5
\n" ); document.write( "AC = 40
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