document.write( "Question 1204129: Solve for R:\r
\n" ); document.write( "\n" ); document.write( "2(pi)R^2 + 2(pi)RH - S = 0 \n" ); document.write( "

Algebra.Com's Answer #840186 by MathLover1(20849) $\"\"$ $\"About$

You can put this solution on YOUR website!
Solve for $\"R+\"$ :\r
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\n" ); document.write( "\n" ); document.write( " $\"2piR%5E2+%2B+2piRH+-+S+=+0+\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"2piR%5E2+%2B+2piRH+=+S+\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"2pi%28R%5E2+%2B+RH%29+=+S+\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"R%5E2+%2B+RH=+S%2F%282pi%29+\"$ ....complete square $\"+R%5E2+%2B+RH+\"$ => $\"%28R%5E2+%2B+RH%2B%28H%2F2%29%5E2%29-%28H%2F2%29%5E2+\"$ => $\"%28R+%2B+H%2F2%29%5E2-%28H%2F2%29%5E2+\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"%28R+%2B+H%2F2%29%5E2-%28H%2F2%29%5E2=+S%2F%282pi%29+\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"%28R+%2B+H%2F2%29%5E2=+S%2F%282pi%29%2B%28H%2F2%29%5E2+\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"R+%2B+H%2F2=+sqrt%28S%2F%282pi%29%2B%28H%2F2%29%5E2%29+\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"R++=+sqrt%28S%2F%282pi%29%2B%28H%2F2%29%5E2%29-H%2F2+\"$ \r
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