document.write( "Question 1204128: An investor bought 300 shares of stock, some at $2.00 per share and some at $3.25 per share. If the total cost was $756.25, how many shares of each stock did the investor buy? (Round to two decimal places if necessary.)
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Algebra.Com's Answer #840180 by mananth(16946)\"\" \"About 
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\n" ); document.write( "Let number of shares at $2.00 be x
\n" ); document.write( "And number of shares at $3,25 be y\r
\n" ); document.write( "\n" ); document.write( "The investor bought 300 shares of stock, \r
\n" ); document.write( "\n" ); document.write( "So, x+y = 300.....................................................(1)\r
\n" ); document.write( "\n" ); document.write( "Investment
\n" ); document.write( " the total cost was $756.25,\r
\n" ); document.write( "\n" ); document.write( "2x+3.25y = 756.25..............................................(2)\r
\n" ); document.write( "\n" ); document.write( "Now x+y = 300 multiply by 2\r
\n" ); document.write( "\n" ); document.write( "2x+2y = 600
\n" ); document.write( "2x+3.25y = 756.25 Subtract the equations ( From (2)\r
\n" ); document.write( "\n" ); document.write( "-1.25y = -156.25\r
\n" ); document.write( "\n" ); document.write( "divide by -1.25\r
\n" ); document.write( "\n" ); document.write( "y = -156.25/ -1.25
\n" ); document.write( "y =125\r
\n" ); document.write( "\n" ); document.write( "x = 300-125= 175\r
\n" ); document.write( "\n" ); document.write( "So, the investor bought 175 shares at $2.00 per share and 125 shares at $3.25 per share.\r
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\n" ); document.write( "\n" ); document.write( "CHECK
\n" ); document.write( "175*2+3.25*125 =756.25\r
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