document.write( "Question 1204124: A rollover IRA of $18,050 was invested in two mutual funds, one earning 12% interest and the other earning 10%. After 1 year, the combined interest income is $2,041. How much (in dollars) was invested at each rate?\r
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Algebra.Com's Answer #840173 by ikleyn(52781) $\"\"$ $\"About$

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\n" ); document.write( "A rollover IRA of $18,050 was invested in two mutual funds, one earning 12% interest
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document.write( "x dollars invested at 12%;  (18050-x) dollars invested at 10%.\r\n" );
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document.write( "Write the total interest equation \r\n" );
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document.write( "    0.12x + 0.1*(18050-x) = 2041  dollars.\r\n" );
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document.write( "To find x from this equation, simplify it step by step\r\n" );
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document.write( "    0.12x + 0.1*18050 - 0.1x = 2041\r\n" );
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document.write( "    0.12x - 0.1x = 2041 - 1805\r\n" );
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document.write( "        0.02x     =    236\r\n" );
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document.write( "           x     =    236/0.02 = 11800.\r\n" );
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document.write( "ANSWER.  $11800 invested at 12%;  the rest 18050 - 11800 = 6250 dollars invested at 10%.\r\n" );
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document.write( "CHECK.   0.12*11800 + 0.1*6250 = 2041 dollars, total interest.   ! correct !\r\n" );
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