document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=115450>Question 115450</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5x/7-6x/5=3/35 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #84016 by </B><A HREF=/tutors/aboutme.mpl?userid=ganesh><B>ganesh(20)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ganesh><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=84016\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Our equation is 5x/7-6x/5=3/35.\r<BR>\n" );
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document.write( "We have to find the value of x.\r<BR>\n" );
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document.write( "LCM of 7 and 5 is 7*5 = 35.\r<BR>\n" );
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document.write( "5x /7 = (5x / 7) *(5/5) = 25x / 35\r<BR>\n" );
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document.write( "6x / 5 = (6x / 5)* (7/7)= 42x / 35<BR>\n" );
document.write( "So, 5x/7 - 6x/5 =  25x/35 - 42x/35 = (25x- 42x)/ 35 = -17x/35\r<BR>\n" );
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document.write( "So, -17x/35 = 3/35<BR>\n" );
document.write( "That is, -17x = 3.<BR>\n" );
document.write( "That is, x = -3/17<BR>\n" );
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