document.write( "Question 1204081: the combined age of 2 brothers is 35 years old.7 years ago one brother was twice the age of the other. how many years apart were they born
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Algebra.Com's Answer #840112 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
\"system%28v%2Bj=35%2Cv-7=2%28j-7%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "OR maybe this way:
\n" ); document.write( "v and 35-v
\n" ); document.write( "\"v-7=2%2835-v-7%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"v-7=2%2828-v%29\"
\n" ); document.write( "\"v-7=56-2v\"
\n" ); document.write( "\"3v=56%2B7\"
\n" ); document.write( "\"3v=63\"
\n" ); document.write( "\"highlight%28v=21%29\"
\n" ); document.write( "and
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\n" ); document.write( "\n" ); document.write( "Those two ages differ by 7 years.
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