document.write( "Question 1204076: An arch is in the shape of a parabola. It has a span of 256 meters and a maximum height of 32 meters.\r
\n" ); document.write( "\n" ); document.write( "a. Find the equation of the parabola.
\n" ); document.write( "b. Determine the distance from the center at which the height is 12 meters.
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Algebra.Com's Answer #840098 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Let the origin be at the center of the base of the arch. The vertex is then (0,32) and the equation is of the form

\n" ); document.write( "\"y=ax%5E2%2B32\"

\n" ); document.write( "Determine the coefficient a using the fact that the feet of the arch are at (-128,0) and (128,0).

\n" ); document.write( "\"0=x%28128%5E2%29%2B32\"
\n" ); document.write( "\"x=%28-32%29%2F%28128%5E2%29=-1%2F512\"

\n" ); document.write( "ANSWER (a): The equation of the arch is \"y=%28-1%2F512%29x%5E2%2B32\"

\n" ); document.write( "To find the distance from the center where the height is 12, set y=12 in the equation and solve for x.

\n" ); document.write( "\"12=%28-1%2F512%29%28x%5E2%29%2B32\"
\n" ); document.write( "\"%281%2F512%29%28x%5E2%29=20\"
\n" ); document.write( "\"x%5E2=20%2A512=10%2A1024=10%2832%5E2%29\"
\n" ); document.write( "\"x=32sqrt%2810%29\"

\n" ); document.write( "That is 101.2 meters, to the nearest tenth.

\n" ); document.write( "ANSWER (b): approximately 101.2 meters

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\n" ); document.write( "Note the second question answered by tutor @MathLover1 is not the question that was asked....

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