document.write( "Question 1204077: How do you graph the parabola of -12(x+3)=(y-3)^2 that includes the directrix and focus on the graph?\r
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document.write( "Focus = (-6,3)
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document.write( "Directrix = x=0
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document.write( "Vertex = (-3,3)\r
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Algebra.Com's Answer #840094 by MathLover1(20850)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "Focus = ( \n" ); document.write( "Directrix = \n" ); document.write( "Vertex = ( \n" ); document.write( "\n" ); document.write( "Two points determine any line. However, since a parabola is curved, we should find more than two points. In this text, we will determine at least five points as a means to produce an acceptable sketch. \r \n" ); document.write( "\n" ); document.write( "To begin, we graph our first parabola by plotting points. Given a quadratic equation of the form \n" ); document.write( "\n" ); document.write( "since you are already given parabola opening sideways and focus is at ( \n" ); document.write( "you are also given two points, use them and use formula to find three more\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "plot these points and sketch the graph\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |