document.write( "Question 1204077: How do you graph the parabola of -12(x+3)=(y-3)^2 that includes the directrix and focus on the graph?\r
\n" ); document.write( "\n" ); document.write( "Focus = (-6,3)
\n" ); document.write( "Directrix = x=0
\n" ); document.write( "Vertex = (-3,3)\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #840094 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"+-12%28x%2B3%29=%28y-3%29%5E2\"
\n" ); document.write( "Focus = (\"+-6\" ,\"+3\" )
\n" ); document.write( "Directrix = \"+x=0\"
\n" ); document.write( "Vertex = (\"+-3\" ,\"+3\" )\r
\n" ); document.write( "\n" ); document.write( "Two points determine any line. However, since a parabola is curved, we should find more than two points. In this text, we will determine at least five points as a means to produce an acceptable sketch. \r
\n" ); document.write( "\n" ); document.write( "To begin, we graph our first parabola by plotting points. Given a quadratic equation of the form \"++-12%28x%2B3%29=%28y-3%29%5E2\" ,\"++x\" is the independent variable and \"+y\" is the dependent variable (so, you choose it). Choose some values for \"+x\" and then determine the corresponding \"+y\" -values. Then plot the points and sketch the graph.\r
\n" ); document.write( "\n" ); document.write( "since you are already given parabola opening sideways and focus is at (\"+-6\" ,\"+3\" ), means the parabola is opening to the \"+left\" and graph will be in II and III quadrant
\n" ); document.write( "you are also given two points, use them and use formula to find three more\r
\n" ); document.write( "\n" ); document.write( "\"+-12%28x%2B3%29=%28y-3%29%5E2\" ...let \"+x=-4\"
\n" ); document.write( "\"+-12%28-4%2B3%29=%28y-3%29%5E2\"
\n" ); document.write( "\"+y=6.46+\" or \"y=-0.46\" \r
\n" ); document.write( "\n" ); document.write( "\"+-12%28x%2B3%29=%28y-3%29%5E2\" ...let \"+x=-10\"
\n" ); document.write( "\"+-12%28-10%2B3%29=%28y-3%29%5E2\"
\n" ); document.write( "\"+y=12.16\" or \"-6.16\" \r
\n" ); document.write( "\n" ); document.write( "\"x+\" |\"y\"
\n" ); document.write( "\"-6\" |\"3\"
\n" ); document.write( "\"-3\" |\"3\"
\n" ); document.write( "\"-4\" |\"6.46\"
\n" ); document.write( "\"-4\" |\"-0.46\"
\n" ); document.write( "\"-10\" |\"12.16\"
\n" ); document.write( "\"-10\" |\"-6.16\" \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "plot these points and sketch the graph\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );