document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1204080>Question 1204080</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if ray QS bisects angle RQT, and if angle RQS=7x+7 and angle RQT=9x+54, find angle SQT.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #840090 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=840090\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if ray QS bisects angle RQT, and if angle RQS=7x+7 and angle RQT=9x+54, find angle SQT. \r<BR>\n" );
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document.write( " Angle RQS  + angle SQT = angle RQT\r<BR>\n" );
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document.write( "Angle SQT = Angle RQT - Angle RQS = Angle SQT\r<BR>\n" );
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document.write( "9x+54 -(7x+7)= Angle SQT\r<BR>\n" );
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document.write( "9x +54 -7x-7 =  Angle SQT\r<BR>\n" );
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document.write( "2x +47 = Angle SQT\r<BR>\n" );
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document.write( "Since ray QS bisects angle RQT Angle RQS  = angle SQT \r<BR>\n" );
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document.write( "7x+7 = 2x+47\r<BR>\n" );
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document.write( "5x = 40\r<BR>\n" );
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document.write( "x =8<BR>\n" );
document.write( "Angle SQT = 2x+47 =63 deg\r<BR>\n" );
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document.write( " </SPAN>\n" );
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