document.write( "Question 1204069: A, B and C are consecutive natural numbers. If 2/7 of the reciprocal of A is equal to ⅓ of the reciprocal of C, find B.
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Algebra.Com's Answer #840079 by ikleyn(52790) $\"\"$ $\"About$

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\n" ); document.write( "A, B and C are consecutive natural numbers. If 2/7 of the reciprocal of A is equal to ⅓ of the reciprocal of C, find B.
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document.write( "Let B = n;  then  A = n-1;  C = n+1.\r\n" );
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document.write( "The equation is\r\n" );
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document.write( "     = ,\r\n" );
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document.write( "or\r\n" );
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document.write( "     = .\r\n" );
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document.write( "To solve, multiply both sides by  7*3*(n-1)*(n+1).  You will get\r\n" );
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document.write( "    2*3*(n+1) = 7*(n-1),\r\n" );
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document.write( "     6(n+1)   = 7(n-1)\r\n" );
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document.write( "     6n + 6   = 7n - 7\r\n" );
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document.write( "     6  + 7   = 7n - 6n\r\n" );
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document.write( "       13    = n.\r\n" );
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document.write( "ANSWER.  The numbers are 12, 13 and 14.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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\n" ); document.write( "\n" ); document.write( "If you read the post by @greenestamps, you will see in the third line\r
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\n" ); document.write( "\n" ); document.write( " \"2/7 of the reciprocal of A is 7/2 times A; 1/3 of the reciprocal of C is 3/1 times C.\"\r
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\n" ); document.write( "\n" ); document.write( "This statement is incorrect. \r
\n" ); document.write( "\n" ); document.write( "For the correct setup, read the posts of other tutors.\r
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