document.write( "Question 1204030: Find the focal diameter for the parabola 34.8y = x^2
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Algebra.Com's Answer #840029 by MathLover1(20850) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( " $\"34.8y+=+x%5E2\"$ \r
\n" ); document.write( "\n" ); document.write( "comparing to $\"4py=x%5E2\"$ , we have\r
\n" ); document.write( "\n" ); document.write( "( $\"h\"$ , $\"k\"$ )=( $\"0\"$ , $\"0\"$ )\r
\n" ); document.write( "\n" ); document.write( " $\"4p=34.8\"$ => $\"p=34.8%2F4\"$ => $\"p=8.7\"$ \r
\n" ); document.write( "\n" ); document.write( "then\r
\n" ); document.write( "\n" ); document.write( "focus: ( $\"0\"$ , $\"8.7\"$ )
\n" ); document.write( "vertex: ( $\"0\"$ , $\"0\"$ )
\n" ); document.write( "semi-axis length: $\"8.7\"$
\n" ); document.write( "focal parameter: $\"2%2A8.7=17.4\"$
\n" ); document.write( "eccentricity: $\"1\"$
\n" ); document.write( "directrix: $\"+y+=+-8.7\"$ \r
\n" ); document.write( "\n" ); document.write( "Focal parameter (the distance between the focus to the directrix) is $\"17.4\"$ .\r
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